288x^2+1440x-5=0

Solution for 288x^2+1440x-5=0 equation:

288x^2+1440x-5=0

a = 288; b = 1440; c = -5;
Δ = b2-4ac
Δ = 14402-4·288·(-5)
Δ = 2079360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2079360}=\sqrt{207936*10}=\sqrt{207936}*\sqrt{10}=456\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1440)-456\sqrt{10}}{2*288}=\frac{-1440-456\sqrt{10}}{576}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1440)+456\sqrt{10}}{2*288}=\frac{-1440+456\sqrt{10}}{576}
$